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feat: ranking tier threshold/#703 #704
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29 changes: 29 additions & 0 deletions
29
src/main/resources/db/migration/V40__update_ranking_tier_thresholds.sql
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,29 @@ | ||
| UPDATE users | ||
| SET current_exp_tier = CASE | ||
| WHEN total_exp >= 50000 THEN 'DIAMOND' | ||
| WHEN total_exp >= 30000 THEN 'GOLD' | ||
| WHEN total_exp >= 10000 THEN 'SILVER' | ||
| WHEN total_exp >= 1000 THEN 'BRONZE' | ||
| ELSE 'UNRANKED' | ||
| END; | ||
|
|
||
| WITH ranked_users AS ( | ||
| SELECT | ||
| id, | ||
| total_exp, | ||
| ROW_NUMBER() OVER (ORDER BY total_exp DESC) AS rank | ||
| FROM users | ||
| WHERE user_status = 'ACTIVE' | ||
| ) | ||
| UPDATE users u | ||
| SET current_rank_tier = CASE | ||
| WHEN ru.rank = 1 AND ru.total_exp >= 150000 THEN 'AURA' | ||
| WHEN ru.rank <= 3 AND ru.total_exp >= 100000 THEN 'MASTER' | ||
| ELSE 'NONE' | ||
| END | ||
| FROM ranked_users ru | ||
| WHERE u.id = ru.id; | ||
|
|
||
| UPDATE users | ||
| SET current_rank_tier = 'NONE' | ||
| WHERE user_status <> 'ACTIVE'; | ||
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ROW_NUMBER()를 사용할 때 ORDER BY total_exp DESC만 지정하면, 경험치가 동일한 유저들 사이의 순위가 비결정적(non-deterministic)으로 정해질 수 있습니다. Java 서비스의 정렬 로직과 일관성을 유지하고 안정적인 결과를 보장하기 위해 id와 같은 고유한 컬럼을 추가 정렬 기준으로 사용하는 것을 권장합니다.